-6.25x^2+6+x=0

Solution for -6.25x^2+6+x=0 equation:

-6.25x^2+6+x=0

a = -6.25; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-6.25)·6
Δ = 151
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{151}}{2*-6.25}=\frac{-1-\sqrt{151}}{-12.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{151}}{2*-6.25}=\frac{-1+\sqrt{151}}{-12.5}
$